Please show that modulus complex number cos 60 degrees+ i sin 60degrees =1.

### 1 Answer | Add Yours

We have given

`cos(60^o)+isin(60^o)=1`

We can write

Z=` (cos(60^o)+isin(60^o))=(1/2)+isqrt(3)/2`

`` mod(z)=`sqrt((1/2)^2+(sqrt(3)/2)^2)`

`=sqrt((1+3)/4)`

`=1`

`=RHS`

### Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes