please show steps to solve: g(x)= (1/2) for g(x)=(x)^2 + 3(x) +4

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So you have `1/2=x^2+3x+4 implies x^2+3x+7/2=0`

Now you use formula for solution of quadratic equation

`x_(1,2)=(-b pm sqrt(b^2-4ac))/(2a)` where `a,` `b` and `c` are coefficients of general quadratic equation `ax^2+bx+c=0.`

Your solutions:

` x_(1,2)=(-3 pm sqrt(3^2-4cdot7/2))/(2)=(-3 pm sqrt(-5))/(2) = `

` (-3 pm i sqrt(5))/(2) `

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