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`N_2+3H_2 harr 2NH_3`
The relationship of `K_p` and `K_c` for the above reaction is given by;
`K_p = K_c(RT)^(Deltan)`
`K_c = 1.2`
`R = 0.08206(Latm)/(Kmol)`
`T = 375+273 = 648K`
= (Total moles in products)-(total moles in reactants)
= `(2-(3+1)) `
`K_p = 1.2xx(0.08206xx648)^(-2)`
`K_p = 4.24xx10^(-4)`
So the answer is `K_p = 4.24xx10^(-4)(atm)^(-1)`
Posted by jeew-m on July 17, 2013 at 1:31 AM (Answer #1)
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