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roshan-rox | Valedictorian

Posted July 17, 2013 at 12:56 AM via web

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jeew-m | College Teacher | (Level 1) Educator Emeritus

Posted July 17, 2013 at 1:31 AM (Answer #1)

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`N_2+3H_2 harr 2NH_3`

 

The relationship of `K_p` and `K_c` for the above reaction is given by;

`K_p = K_c(RT)^(Deltan)`

 

`K_c = 1.2`

`R = 0.08206(Latm)/(Kmol)`

`T = 375+273 = 648K`

`Deltan `

= (Total moles in products)-(total moles in reactants)

= `(2-(3+1)) `

`= -2`

 

`K_p = 1.2xx(0.08206xx648)^(-2)`

`K_p = 4.24xx10^(-4)`

 

So the answer is `K_p = 4.24xx10^(-4)(atm)^(-1)`

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