# What is the solution of 3x + 8y = 92 and 2x - 6y = 16.

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The set of linear equations 3x + 8y = 92 and 2x - 6y = 16 have to be solved.

3x + 8y = 92 ...(1)

2x - 6y = 16 ...(2)

2x - 6y = 16

=> x = 8 + 3y

Substitute in (1)

=> 3(8 + 3y) + 8y = 92

=> 24 + 9y + 8y = 92

=> 17y = 68

=> y = 4

x = 20

**The solution of the given set of equations is x = 20, y = 4**

3x + 8y = 92

2x - 6y = 16

First multiply everything in the top equation by 2 and everything in the bottom equation by 3

By doing that, you should get

**6x + 16y = 184**

**6x - 18y = 48 **now subtract 6x with 6x (which means also subtract 16y with 18y and 184 with 48)

By subtracting, you should get

**34y = 136 **now divide both sides by 34

By dividing, you should get

**y = 4 **which is your answer for " y "

Now plug 4 into one of the equation

**2x - 6 ( 4 ) = 16 **Multiply -6 with 4

By multiplying, you should get

**2x -24 = 16 **now add 24 on both sides

By adding, you should get

**2x = 40 **now divide both sides by 2

By dividing, you should get

**x = 20 **which is your answer for " x "

So your answer is **x = 20 ; y = 4**