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Please help solve the third question down (6 x5=...) and show how.
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Whenever you have a to take the n-th root from a number you need to raise that number to a fractional power having as numerator 1 and as denominator `n` . Thus
`root(6)(x^5) =(x^5)^(1/6) =x^(5*1/6) =x^(5/6)`
We have to take the 6-th root from the number `x^5` . Equivalent, we raise the number `x^5` to the power `1/6` . Then we use the powers properties to transform `(x^5)^(1/6)` into the number `x^(5/6)` .
Posted by valentin68 on October 31, 2013 at 6:33 PM (Answer #1)
Salutatorian, TA, Tutor
`root(6)(x^5)` , where n=6 and x=`x^5`
Substitute the variables and you get
`(x^5)^(1/6)` , which can be simplified to
Posted by michuraisin on November 1, 2013 at 4:36 AM (Answer #2)
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