Please help me solve the following math problems: `((t^2+3t-18)/(t^2+2t-15))((t^2-3t-10)/(t^2+8t+12))` (Only one question, and one related follow up question, please)



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Posted on (Answer #1)

The first step is to factor the 4 polynomials.  Find two numbers that multiply to the last term, and add to the constant of the second term:

6+-3=3 and (6)(-3)=-18

-5+2=-3 and (-5)(2)=10

5+-3=2 and (5)(-3)=-15

6+2=8 and (6)(2)=12



`((t^2+3t-18)/(t^2+2t-15))((t^2-3t-10)/(t^2+8t+12))=(((t+6)(t-3))/((t+5)(t-3)))(((t-5)(t+2))/((t+6)(t+12))) `

Cancel out the equivalent terms, and you are left with:



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