`(e^2^y +1)/(e^2^y) (dy)` Please find the indefinite integral. Topic: Math 1 Answer | Add Yours Top Answer hala718 | High School Teacher | (Level 1) Educator Emeritus Posted on May 23, 2012 at 9:46 PM (Answer #1) `int (e^(2y) +1)/(e^(2y)) dy` `= int (e^(2y))/e^(2y) + 1/e^(2y) dy` `= int 1 + e^(-2y) dy` `= y + e^(-2y)/(-2) + C` `= y - 1/(2e^(2y)) + C` `` `int (e^(2y) +1)/(e^(2y)) dy` `= int (e^(2y))/e^(2y) + 1/e^(2y) dy` `= int 1 + e^(-2y) dy` `= y + e^(-2y)/(-2) + C` `= y - 1/(2e^(2y)) + C` `` We’ve answered 287,495 questions. We can answer yours, too. Ask a question

Top Answer hala718 | High School Teacher | (Level 1) Educator Emeritus Posted on May 23, 2012 at 9:46 PM (Answer #1) `int (e^(2y) +1)/(e^(2y)) dy` `= int (e^(2y))/e^(2y) + 1/e^(2y) dy` `= int 1 + e^(-2y) dy` `= y + e^(-2y)/(-2) + C` `= y - 1/(2e^(2y)) + C` `` `int (e^(2y) +1)/(e^(2y)) dy` `= int (e^(2y))/e^(2y) + 1/e^(2y) dy` `= int 1 + e^(-2y) dy` `= y + e^(-2y)/(-2) + C` `= y - 1/(2e^(2y)) + C` ``