# `(e^2^y +1)/(e^2^y) (dy)` Please find the indefinite integral.

### 1 Answer | Add Yours

`int (e^(2y) +1)/(e^(2y)) dy`

`= int (e^(2y))/e^(2y) + 1/e^(2y) dy`

`= int 1 + e^(-2y) dy`

`= y + e^(-2y)/(-2) + C`

`= y - 1/(2e^(2y)) + C`

``

`int (e^(2y) +1)/(e^(2y)) dy`

`= int (e^(2y))/e^(2y) + 1/e^(2y) dy`

`= int 1 + e^(-2y) dy`

`= y + e^(-2y)/(-2) + C`

`= y - 1/(2e^(2y)) + C`

``