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A piece of modeling clay is rolled into a cylinder and its resistance R is measured...
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Let volume of the cay be V cubic unit, length be initial be L and radius circular of cross section be r.Thus
`V=pi r^2 L` (i)
when legth of cylinder doubled i.e 2L ,since volume remain same so radius of circular cross section will reduced to `r_1` (say). So volume will be
`V=2pir^2_1L ` (ii)
From (i) and (ii) we have
let `R_1` be the resistance when legth 2L
`R_1=rho(2L)/(pir^2_1)` , usin (iii) ,we will get
From (iv) and (v) ,we have
Posted by pramodpandey on March 27, 2013 at 8:44 AM (Answer #1)
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