Homework Help

A piece of ice of mass 40 g is added to 200 g of water at 50 deg C.Calculate the final...

user profile pic

topperoo | Student, Grade 10 | (Level 1) Salutatorian

Posted July 23, 2012 at 12:05 PM via web

dislike 1 like

A piece of ice of mass 40 g is added to 200 g of water at 50 deg C.Calculate the final temperature of water when all ice has melted.

Specific heat capacity of water=4200 J kg-1K-1

Specific latent heat of fusion of ice=336 X 1000 J/kg

I am in Class X and I need this answer today only.

1 Answer | Add Yours

user profile pic

jeew-m | College Teacher | (Level 1) Educator Emeritus

Posted July 26, 2012 at 12:12 AM (Answer #1)

dislike 1 like

Let the final temperature is x deg.C

The heat absorbed or diffused is given by `Q=mc(theta)`

What will happen here is that;

  • Ice will melt at 0 deg.C using its Specific latent heat of fusion
  • Then the melted ice at 0 deg will increase the temperature up to x deg C
  • The water will reduce temperature allowing ice to melt.

 

Therefore;

Heat absorbed by ice = Heat diffused by water

 

Heat absorbed by ice at latent heat = 336*1000*40/1000J= 13440J

Heat absorbed by ice when heating to x deg = `mc(theta)`

                                                               = 40/1000*4200*(x-0)

                                                               = 168x

 

Heat diffused by water = 200/1000*4200*(50-x)

                                 = 840(50-x)

 

So;

168x + 13440 = 840(50-x)

                x   = 28.3333

 

So the final temperature is 28.333 deg.C

Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes