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Given the gravitational acceleration on the surface of the moon is 1/6 of that of the...
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Along with the Three Laws of Motion for which Newton is famous, he also developed the Universal Law of Gravitation. According to the Universal Law of Gravitation, the force of attraction between two objects with mass is given by
Fg = -G M1M2/r^2 where G is the universal gravitational constant, M1 and M2 are the two masses attracting each other, and r is the distance of separation between their centers. If we compare this to the equation for the weight of an object W = Mg where M is the object being attracted we can see that at the surface of the Moon
Fg = W
-GM1M/r^2 = Mg or
g = -GM1/r^2, we can now solve this for r which will be the radius of the Moon
r =sqrt(-GM1/g), plugging the given information into this relationship we get
r = 1.76x10^6m
Posted by mwmovr40 on April 27, 2012 at 2:31 AM (Answer #1)
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