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The perimeter of rectrangular field is 172 meters. Double the width is 4 meters more...

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bcorong | (Level 1) eNoter

Posted September 27, 2012 at 6:05 AM via web

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The perimeter of rectrangular field is 172 meters. Double the width is 4 meters more than the length. Find the area of the field.

I would like to know what is the equation to use to solve the problem.

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted September 27, 2012 at 8:51 AM (Answer #1)

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The perimeter of rectangular field is 172 meters.

Let the width of the field be W = X. Twice the width of the field is 4 more than the length. The length is equal to L = 2*X - 4.

The perimeter of the rectangular field is 2*(W + L)

=> 2*(X + 2*X - 4)

=> 6x - 8

6X - 8 = 172

=> X = 30

The area of the field is W*L = 30*56 = 1680 square meters.

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subhaditya18 | Student | (Level 1) Honors

Posted September 27, 2012 at 7:39 AM (Answer #2)

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perimeter=2(l+b)
perimeter=172 m
area=lb
l=2w -4
perimeter=2({2w-4}+w)
=4w-8+2w
=6w-8
172=6w-8
6w=172+8
=180
w=180/6
=30m
l=(2x30)-4
=60-4
=56m
area=56x30
=1680 sq. m (ans)
Here w is width and l is length

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