The perimeter of rectrangular field is 172 meters. Double the width is 4 meters more than the length. Find the area of the field.
I would like to know what is the equation to use to solve the problem.
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The perimeter of rectangular field is 172 meters.
Let the width of the field be W = X. Twice the width of the field is 4 more than the length. The length is equal to L = 2*X - 4.
The perimeter of the rectangular field is 2*(W + L)
=> 2*(X + 2*X - 4)
=> 6x - 8
6X - 8 = 172
=> X = 30
The area of the field is W*L = 30*56 = 1680 square meters.
=1680 sq. m (ans)
Here w is width and l is length
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