# Perform the indicated math on the two vectors: (23, 13) minus (34∠-37°)a. (50,-7.5) b.(-4.15, 33.4) c.(-4.15, -7.46) d. (-11, 50)

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You need to transform the polar coordinates of the vector `(34 lt -37^o)` into cartesian coordinates such that:

`cos(-37^o) = x/34 =gt 34cos 37^o = x =gt x = 27.15`

`sin(-37^o) = y/34 =gt y = -34sin(37^o) =gt y = -20.46`

Hence, you need to perform the subtraction such that:

`(23, 13) - (34 lt -37^o) = (23, 13) - (27.15 , -20.46)`

`(23, 13) - (34 lt -37^o) = (23 - 27.15 , 13 + 20.46)`

`(23, 13) - (34 lt -37^o) = (-4.15 , 33.46)`

**Notice that the b. answer represents the correct option in this case, hence `(23, 13) - (34 lt -37^o) = (-4.15 , 33.46).` **

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