Better Students Ask More Questions.
If the percentage yield for the combustion reaction of methane is 92%.What mass of CO2...
1 Answer | add yours
`CH_4+2O_2 rarr CO_2+2H_2O`
`CH_4 = 16g/(mol)`
`CO_2 = 44g/(mol)`
Amount of `CH_4` burned
`= 75/16 mol`
`= 4.6875 mol`
`CH_4:CO_2 = 1:1`
Theretical amount of `CO_2 ` produced
`= 4.3125 mol`
Amount of `CO_2` yield
`= 4.3125xx44 g`
So the `CO_2` yield is 189.75g.
Posted by jeew-m on April 19, 2013 at 3:47 AM (Answer #1)
Join to answer this question
Join a community of thousands of dedicated teachers and students.