What is the magnitude of the particle's acceleration in the following case:

A particle moves in the x-y plane with coordinates given by x=A cos wt and y= A sin wt, where A=1.5 meters and w= 2.0 radians per second .

**What is the magnitude of the particle's acceleration? **

1. ||a|| = 3.0 m/s^2

2. ||a|| = 6.0 m/s^2

3. ||a|| = 1.3 m/s^2

4. ||a|| = 4.5 m/s^2

5. ||a|| = 0 m/s^2

### 1 Answer | Add Yours

The x-coordinate of the position of the particle is given by A*cos w*t. Here w = 2 radians/second and A = 1.5 m.

The x-coordinate of the position of the particle is: 1.5*cos 2*t

dx/dt = 1.5*2*(-sin 2*t)

d^2x/dt^2 = -6*cos 2t

The y-coordinate of the position of the particle is: 1.5*sin 2*t

dy/dt = 1.5*2*cos 2t

d^2y/dt^2 = -6*sin 2t

The magnitude of the acceleration is sqrt((-6*cos 2t)^2+(-6*sin 2t))

=> 6*sqrt((sin 2t)^2 + (cos 2t)^2)

=> 6

**The magnitude of the acceleration of the particle is option 2 or 6 m/s^2**

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