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A particle moves with acceleration `a(t)` m/s^2 along an s-axis and has velocity...
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The distance D traveled by a particle in a duration of time t is D = u*t + (1/2)*a*t^2 where u is the the initial velocity and a is the acceleration.
If the acceleration of the particle is 9 m/s^2 and the initial velocity is -1 m/s:
distance traveled in 0 seconds is 0
distance traveled in 2 seconds is -1*2 + 0.5*9*4 = 16
The distance traveled by the particle in the given time interval is 16 m, this is the same as its displacement.
Posted by justaguide on August 10, 2013 at 4:53 PM (Answer #1)
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