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A parabola has a Vertex V = (6,4) and a Focus F = (6,-1).  What is the equation?...

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kristenmarieb... | Student, Grade 10 | Valedictorian

Posted July 9, 2013 at 7:19 PM via web

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A parabola has a Vertex V = (6,4) and a Focus F = (6,-1).  What is the equation?  Determine the 4p value

Enter the equation in the form:

(x-h)^2 = 4p(y-k)   or   (y-k)^2 = 4p(x-h)

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted July 9, 2013 at 7:46 PM (Answer #1)

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The vertex of the parabola is at (6, 4) and the focus is at (6, -1).

This is a parabola that opens downwards. The focus is 5 units below the vertex. This gives p = -5 or 4p = -20

The equation of the parabola in the required form is : (x - 6)^2 = -20*(y - 4)

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