p(t)=5t^2+29t+200 Find the growth rate after 2 hours
1 Answer | Add Yours
The function p(t)=5t^2+29t+200. The rate of change of p(t) with respect to t is p'(t) = 10t + 29.
At t = 2, p'(t) = 20 + 29 = 49
The rate of growth of p(t) at t = 2 is equal to 49.
Join to answer this question
Join a community of thousands of dedicated teachers and students.Join eNotes