# p(t)=5t^2+29t+200 Find the growth rate after 2 hours

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The function p(t)=5t^2+29t+200. The rate of change of p(t) with respect to t is p'(t) = 10t + 29.

At t = 2, p'(t) = 20 + 29 = 49

**The rate of growth of p(t) at t = 2 is equal to 49.**