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Numerical problemThe density of sea water is 1.025 g/cc and that of iceberg 0.917 g/cc....
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Let V be the total volume of ice and V' be the volume of ice submerged in water.
The volume of water displaced = V'
Bouyancy force exerted upwards is equal to the weight of iceberg.
`B = W`
`V ' xx 1.025 xx g = V xx 0.917 xx g`
Where g is the gravitational acceleration.
`(V')/V = 0.917/1.025`
The percentage of volume submerged is,
`(V')/V xx 100 = 0.917/1.025 xx 100 %`
`(V')/V xx 100 = 89.46 %`
Therefore, 89.46 % of iceberg is inside sea water.
Posted by thilina-g on May 31, 2012 at 2:06 PM (Answer #1)
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