solve for x: `2log_b x= log_b 4 + log_b(x-1).`
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Since,` alog_bx=log_bx^a` and ` log_bx+log_by=log_bxy` we get:
Therefore, the required value of x is 2.
your question is ,Apply laws of log and solve the problem.I hope you know laws of log.Log defined only for positive number more than 0.
`x>0 ,x-1>0` this implies `x>1` .
Now take your question.
`` taking antilog both side
So answer to your question x=2
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