# Need help w/Algebra pertaining to square roots.What is the square root of C to the 2ndpower minus 2c +1.Step by step explanation wld be appreciated.

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You need to evaluate the square root of development `c^2 - 2c + 1` .

Notice that the development `c^2 - 2c + 1 ` represents the binomial `(c-1)^2` , hence, you may evaluate the square root of the binomial squared such that:

`sqrt(c^2 - 2c + 1) = sqrt((c-1)^2)`

`sqrt(c^2 - 2c + 1) = |(c-1)|`

`|(c-1)| = c-1 if c-1gt=0`

`|(c-1)| = -c+1 if c-1lt0`

**Hence, evaluating the square root of `c^2 - 2c + 1` yields `sqrt((c-1)^2) = |(c-1)|.` **

**Sources:**

The square root of

c^2 - 2c + 1

is to be found. Note that this trinomial can be factored.

(c - 1) (c - 1) or (c - 1)^2

So, the square root is c - 1.

Square root of ( c^2 - 2c + 1)

c^2 - 2c +1 = ( c - 1) ^2 [Using expansion formula: (a - b)^2 = a^2- 2ab + b^2 ]

(c -1 )^2 = (c - 1)(c - 1)

Therefore sq.root of ( c - 1)^2 = sq.root of (c -1)(c -1) =**(c -1) Answer**