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n=2000,x=400, 95% confidenceUse the sample data and confidence level to construct the...
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High School Teacher
95% confidence level implies `alpha=.05,alpha/2=.025`
The confidence interval we seek is `hatp-z_(alpha/2)sqrt((hatp(1-hatp))/n)<p<hatp+z_(alpha/2)sqrt((hatp(1-hatp))/n)`
From a table, `z_(alpha/2)=z_(.025)=1.96`
So p lies between 16.6% and 23.4% with a 95% confidence level.
Posted by embizze on May 30, 2012 at 9:10 PM (Answer #1)
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