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Multiply. A) (2xy^3)(9x^2y^5)   B)(8a)(2a^3b)(0)

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treysongzlove... | Student, College Freshman | eNoter

Posted April 16, 2013 at 1:51 PM via web

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Multiply. A) (2xy^3)(9x^2y^5)   B)(8a)(2a^3b)(0)

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted April 16, 2013 at 2:12 PM (Answer #1)

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The result of (2xy^3)(9x^2y^5)

= 2*9*x*x^2*y^3*y^5

= 18*x^3*y^8

For (8a)(2a^3b)(0) as one of the terms is 0, the result is 0.

The required products are (2xy^3)(9x^2y^5) = 18*x^3*y^8 and (8a)(2a^3b)(0) = 0

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sciencesolve | Teacher | (Level 3) Educator Emeritus

Posted April 16, 2013 at 3:00 PM (Answer #2)

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A)Using the following exponential law yields:

`a^x*a^y = a^(x+y)`

Reasoning by analogy, yields:

`(2*x*y^3)*(9*x^2*y^5) = (2*9)*(x^(1+2))*(y^(3+5))`

`(2*x*y^3)*(9*x^2*y^5) = 18*x^3*y^8`

B) Since one factor is 0,you need to use zero product rule, such that:

`(8a)(2a^3b)(0) = 0`

Hence, evaluating the multiplications, yields `A) `

`18*x^3*y^8, B) 0. `

 

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atyourservice | TA , Grade 10 | Valedictorian

Posted March 22, 2014 at 4:24 PM (Answer #3)

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 (2xy^3)(9x^2y^5)   B)(8a)(2a^3b)(0)

`(2xx x xx y^3)(9xx x^2 xx y^5) `

`2xx x xx y^3xx9xx x^2 xx y^5`

`2xx9xx x xx x^2xxy^2xxy^5 `

`18xx x^3xxy^8 `

`(8a)(2a^3b)(0) = 0` because anything multiplied by 0 is immediately 0

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