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A monovalent ion enters into a plane-parallel capacitor. The entrance angle, alfa=30...
A monovalent ion enters into a plane-parallel capacitor. The entrance angle, alfa=30 degrees,up against armatures.Find the kinetik energy of the ion.
The ion comes out by keeping the same entrance angle(the value is positive).
The length of capacitor is l=10cm and electric field intensity, E=40KV/m.
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Best answer as selected by question asker.
The problem is analogue to oblique projection in gravitational field, the only difference being that instead of gravitational acceleration g, we'll have the acceleration a=e*E/m
Then, the length of capacitor represents "tha range"
l=(v0^2/a)*sin 2 alfa=[m*v0^2/(e*E)]*sin 2 alfa
The kinetic energy is the semiproduct between the weight of the particle and it's square speed:
Ek=m*v0^2/2=e*E*l/(2 sin 2 alfa=0.37fJ=2.3KeV
Posted by giorgiana1976 on June 29, 2009 at 4:23 AM (Answer #1)
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