A monovalent ion enters into a plane-parallel capacitor. The entrance angle, alfa=30 degrees,up against armatures.Find the kinetik energy of the ion.
The ion comes out by keeping the same entrance angle(the value is positive).
The length of capacitor is l=10cm and electric field intensity, E=40KV/m.
1 Answer | Add Yours
The problem is analogue to oblique projection in gravitational field, the only difference being that instead of gravitational acceleration g, we'll have the acceleration a=e*E/m
Then, the length of capacitor represents "tha range"
l=(v0^2/a)*sin 2 alfa=[m*v0^2/(e*E)]*sin 2 alfa
The kinetic energy is the semiproduct between the weight of the particle and it's square speed:
Ek=m*v0^2/2=e*E*l/(2 sin 2 alfa=0.37fJ=2.3KeV
We’ve answered 333,453 questions. We can answer yours, too.Ask a question