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a monochromatic light passes from glass into air. When the incident angle of `theta`...
a monochromatic light passes from glass into air. When the incident angle of `theta` equals 30 degrees, the refraction angle of `phi` equals 45 degrees. The absolute refractive index of air `n_A` is 1. Let the frequency of the monochromatic light be 5x10^4 Hz.
Find the absolute refractive index of glass, `n_G`
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According to Snell's law, considering refraction of light from glass into air,
Plugging in the values,
`sin30/sin45 = 1/n_G`
`rArr n_G=sqrt2 = 1.414` (approximately).
Therefore, the absolute refractive index of glass `n_G=1.414`
Posted by llltkl on July 5, 2013 at 5:48 PM (Answer #1)
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