In a mixture of N2 and O2 gases, the mol fraction of N2 is found to be 0.700. The total pressure of the mixture is 1.42 atm. What is the partial pressure of O2 in the mixture? 



1 Answer | Add Yours

jeew-m's profile pic

Posted on (Answer #1)

We have `N_2` and `O_2` in the gas mixture. Mole fraction of `N_2` is 0.7

`X_(N_2) = 0.7`

Since mole fraction of both gasses add up to 1;

`X_(O_2) = 1-0.7 = 0.3`


Total pressure `(P_T) = 1.42atm`


Partial pressure = (mole fraction)`xx` (total pressure)

`P_(O_2) = X_(O_2)xxP_T`

`P_(O_2) = 0.3xx1.42 = 0.426atm`


So the partial pressure of `O_2` is 0.426atm.



Both gasses act as ideal gasses.

We’ve answered 287,480 questions. We can answer yours, too.

Ask a question