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In a mixture of N2 and O2 gases, the mol fraction of N2 is found to be 0.700. The total...
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We have `N_2` and `O_2` in the gas mixture. Mole fraction of `N_2` is 0.7
`X_(N_2) = 0.7`
Since mole fraction of both gasses add up to 1;
`X_(O_2) = 1-0.7 = 0.3`
Total pressure `(P_T) = 1.42atm`
Partial pressure = (mole fraction)`xx` (total pressure)
`P_(O_2) = X_(O_2)xxP_T`
`P_(O_2) = 0.3xx1.42 = 0.426atm`
So the partial pressure of `O_2` is 0.426atm.
Both gasses act as ideal gasses.
Posted by jeew-m on June 12, 2013 at 8:20 PM (Answer #1)
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