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A minute sample of AlCl3 is analyzed for chlorine. The analysis reveals that there are...
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`AlCl_3 rarr Al^(3+)+3Cl^-`
`Al^(3+):Cl^(-) = 1:3`
So we would have 1/3 of `Al^(3+)`than the amount of chloride.
Amount of `Al^(3+) = 1/3*24 = 8`
So we have 8 moles of `Al^(3+)`
`AlCl_3:Cl^(-) = 1:3`
So we would have `1/3` of `AlCl_3`than the amount of chloride.
Amount of `AlCl_3 = 1/3*24 = 8`
So we have 8 moles of` AlCl_3` .
Molar mass of `AlCl_3 = 133.5g`
Mass of `AlCl_3 = 8*133.5 = 1068g`
So total mass of `AlCl_3` in the sample is 1068g.
Posted by jeew-m on June 19, 2013 at 12:43 AM (Answer #1)
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