Homework Help

A minute sample of AlCl3 is analyzed for chlorine. The analysis reveals that there are...

user profile pic

lak-86 | Student, Undergraduate | (Level 1) Salutatorian

Posted June 19, 2013 at 12:30 AM via web

dislike 1 like

A minute sample of AlCl3 is analyzed for chlorine. The analysis reveals that there are 24 chloride ions present in the sample. Find the amount of Aluminium ions and total mass of AlCl3.

1 Answer | Add Yours

user profile pic

jeew-m | College Teacher | (Level 1) Educator Emeritus

Posted June 19, 2013 at 12:43 AM (Answer #1)

dislike 1 like

`AlCl_3 rarr Al^(3+)+3Cl^-`


Mole ratio

`Al^(3+):Cl^(-) = 1:3`

So we would have 1/3 of `Al^(3+)`than the amount of chloride.

Amount of `Al^(3+) = 1/3*24 = 8`

So we have 8 moles of `Al^(3+)`


`AlCl_3:Cl^(-) = 1:3`

So we would have `1/3` of `AlCl_3`than the amount of chloride.

 

Amount of `AlCl_3 = 1/3*24 = 8`

So we have 8 moles of` AlCl_3` .

 

Molar mass of `AlCl_3 = 133.5g`


Mass of `AlCl_3 = 8*133.5 = 1068g`

 

So total mass of `AlCl_3` in the sample is 1068g.


Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes