math questionHow to differentiate y = cos x*ln x?



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Posted on (Answer #2)

We'll have to differentiate with respect to x, using the product rule:

(u*v)' = u'*v + u*v'

Let u = cos x and v = ln x

y' = (cos x)'*(ln x) + (cos x)*(ln x)'

y' = -sin x*ln x + (cos x)/x

The first derivative of the function is y' = -sin x*ln x + (cos x)/x


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