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MathA worm is at the bottom of a forty meter hole. It can crawl upwards at the rate of...

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elekzy | Student, Grade 11 | (Level 1) Valedictorian

Posted March 13, 2012 at 2:20 PM via web

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Math

A worm is at the bottom of a forty meter hole. It can crawl upwards at the rate of four meters in one day, but at night, it slips back three meters. At this rate, how long will it take the worm to crawl out of the hole?

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pohnpei397 | College Teacher | (Level 3) Distinguished Educator

Posted March 13, 2012 at 2:30 PM (Answer #2)

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I think it should take it 37 days.  It should make it out of the hole on the 37th day because it will get out of the hole before night and so it won't slip back.  On day 36, it should get up to 39 meters and slip back to 36 meters in the night.  On day 37, it will go up 4 more meters and get out of the hole.

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pacorz | High School Teacher | (Level 3) Educator

Posted March 13, 2012 at 10:29 PM (Answer #3)

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I did the math out and I agree with pohnpei that on day 37, the worm hits the 40 meter mark and should be able to get out of the hole.

Basically, the worm gains one meter per day, because he climbs 4 and slides back 3, and 4-3=1. So the morning of day 37, when the worm begins at 36 meters from the bottom, it will climb the last 4 meters and exit from the hole.

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litteacher8 | Middle School Teacher | (Level 1) Distinguished Educator

Posted March 13, 2012 at 11:57 PM (Answer #4)

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Yes, it is pretty simple.  You solve this by taking the total distance the worm travels and subtracting the amount it slips back.  Four minus three is one.  So it climbs a meter a day, but on the last day it won't slip back and it gets out.  Persistent worm!

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wannam | High School Teacher | (Level 3) Educator

Posted March 14, 2012 at 1:35 AM (Answer #5)

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If you find this type of word problem confusing, you might find drawing a picture helpful. I am a very visual learner and I used to draw out this type of problem. Even when I advanced into complicated math, I would still draw a sketch to double check my answers. If you are a hands on learner or a visual learner, drawing a sketch and physically tracing the worms path in the hole can be very helpful to understanding this type of word problem.
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elekzy | Student, Grade 11 | (Level 1) Valedictorian

Posted March 14, 2012 at 12:36 PM (Answer #6)

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Well, if you got 37 days, you are right.

At the end of day one, the worm would be at the one meter mark. At the end of the 35th day, the worm would be at the 35th meter mark. On the 36th day, the worm travels from 35 meters to 39 meters but slips back to 36 meters at the end of the 36th day. On the 37th day, the worm travels up 4 meters from the 36th meter and is consequently out of the hole!

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lnj100 | Student, Grade 10 | (Level 1) Valedictorian

Posted March 30, 2012 at 3:23 AM (Answer #7)

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37 days. On the 37th it crawls all the way to the top, and hence doesn't slide down again.

On the 36th day he only gets up to 39m (before sliding back to 36). Each day has a net gain of 1m, so his starting point on any given day is x-1m, where x is the number of days. He starts at 0m on day 1, 1m on day 2, etc. Therefore the highest point he reaches on any given day is x-1+4, or x+3. So on the first day he gets to four metres, on the second he gets to five, on the third he gets to six and so on. It isn't until the 37th day that he reaches the top of the hole.
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just-s | Student, Grade 11 | (Level 1) Valedictorian

Posted April 4, 2012 at 5:38 PM (Answer #8)

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erm 37 days as well i think!!

 

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prabudh | Student, Grade 9 | (Level 1) Honors

Posted April 10, 2012 at 3:33 PM (Answer #9)

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37 days

the answer is surely correct

 

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yaozhang | (Level 3) eNoter

Posted April 17, 2012 at 6:21 AM (Answer #10)

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37 days, because on day 37 it crawls up to the top.

I hope it doesn't slide down again though ^ ^

And well, it's very slow! >__<

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