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A magnetic force of 5.28X10^-6N acts on a particle of unknown charge traveling through...

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andrewmezzo | Student | Valedictorian

Posted March 31, 2013 at 5:02 PM via web

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A magnetic force of 5.28X10^-6N acts on a particle of unknown charge traveling through a magnetic field. The speed of the particle is 5.50x10^4m/s and the magnetic field is 3X10^-2T. 

 

Calculate the charge of the particle an the number of elementary charges the particle carries.

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sciencesolve | Teacher | (Level 3) Educator Emeritus

Posted March 31, 2013 at 5:49 PM (Answer #1)

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You need to use the following equation to evaluate the charge of magnetic field, such that:

`F_B = Q*v*B => Q = (F_B)/(v*B)`

Since the problem provides `F_B = 5.28*10^(-6)N` ,  yields:`v = 5.5*10^4 m/s` and `B = 3*10^(-2)T` ,

`Q = (5.28*10^(-6))/(5.5*10^4*3*10^(-2))`

`Q = 0.32*10^(-8) C`

You need to evaluate the number of elementary charges, such that:

`Q = n*q => n = Q/q => n = (0.32*10^(-8))/(1.6*0^(-19))`

`n = 0.2*10^11 => n = 2*10^10 e`

Hence, evaluating the charge of particle Q and the number of elementary charges n, under the given conditions, yields `Q = 0.32*10^(-8) C` and `n = 2*10^10 e.`

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