A magnetic circuit has a 20 cm lenght core with a permeability of 0.005 Wb/(Atm). The coil has 250 turns, and draws 0.4 ampere. Determine the flux density.



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Posted on (Answer #1)

The magnetic flux density due to a coil is given by,


`=(mu*N*I)/l` (Where mu is the permeability of the solenoid, N, the number of turns, I, the current strength and l, the path length)

Plugging in the values,


`=2.5` Wb/m^2

`=2.5 T` 

Therefore, the flux density of the coil is 2.5 T.


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