m= 3, (5,1)

what is The equation of the line

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SINCE y-y1=m(x-x1)

so

y-1=3(x-5)

y-1=3x-15

y-3x=-14 ------------------answer

HOPE THIS HELPS ...

You can use point slope

`y-y_0=m(x-x_0)`

In this case

` `` ``x_0 = 5, y_0 = 1 "and m = 3`` `

``So

y - 1 = 3(x - 5)

Distributing

y - 1 = 3x - 15

y = 3x - 14

We could also use

y=3x+b

Substitute (1,5) into this equation

1=3(5)+b

1=15+b

b = -14

So our answer is y = 3x - 14

slope of a line equals y=mx+b

insert your slope of 3 into this formula

so now you have y=3x+b

then insert your point of (5,1) (remember, point is (x,y))

then simply solve for b

1=3(5)+b

1=15+b

(subtract 15 from both sides)

-14=b

plug in your b into your (y=3x+b) equation and you are done

y=3x-14

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