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The length of one side of the right triangle is equal to 16 and the length of the hypotenuse is equal to 54.
Let the angle adjacent the side be denoted by X.
`cos X = 16/54 = 8/27`
`X = cos^-1(8/27)`
=> `X ~~ 72.76` degrees
The measure of the angle adjacent to the side with length 16 is approximately 72.76 degrees.
Take ABC traingle
B is 90 degreee
AC = 54
Then the required angle(say x) is between AB and AC
Cos (x)= BC/AC
(x) = Cos inverse (BC/AC)(x) = Cos inverse (0.2963)(x) =72.6 degreeSo the answer is 72.6 degree
Let us take the right angle triangle ABC , where angle B= 90 degree.
Then according to the question One leg i.e side BC=16 and the
hypotenuse AC= 54. We require to find the measure of angle ACB.
Let angle ACB = x.
Let us take cosine of the angle ACB i.e cos(x).
We know that cosine of an angle A i.e. cos(A) = base/hypotenuse
Applying this we get :
cos(x) = BC/AC = 16/54 = 8/27 = 0.2963
Since cos(x) = 0.2963
hence, x = 72.6 degrees <---Answer
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