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We have : log3(8x+3) = 1+ log3 (x^2)

log3(8x+3) = 1+ log3 (x^2)

=> log3(8x+3) - log3 (x^2) = 1

use the property log a - log b = log (a/b)

=> log3 [(8x + 3)/(x^2)] = 1

=> (8x + 3)/(x^2) = 3

=> 8x + 3 = 3x^3

=> 3x^2 - 8x - 3 = 0

=> 3x^2 - 9x + x - 3 = 0

=> 3x(x - 3) + 1(x - 3) = 0

=> (3x + 1)(x - 3)= 0

=> x = -1/3 and x = 3

Both the values are defined for the logs given.

**The solution of the equation is x = -1/3 and x = 3**

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