What is x if log(x) (1/8) = -3/2.

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Given that log(x) (1/8) = -3/2

We need to find the values of x.

==> Let us simplify.

First we will rewrite (1/8) = (1/2)^3

==> (1/2)^3 = 2^-3

==> log(x) 2^-3 = -3/2

Now we know that log a^b = b*log a

==> log(x) 2^-3 = -3*log(x) 2 = -3/2

We will divide by -3.

==> log(x) 2 = -3/2*-3 = 1/2

Now we will rewrite using exponent form.

==> x^1/2 = 2

We will square both sides.

**==> x = 4**

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