If log(base7)(x^2) = log(base3)(9), then what is the absolute value of x.

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`log_7 (x^2) = log_3 (9)`

We know that;

`log_a(b^2) = 2log_a(b)`

`log_7 (x^2) = log_3 (3^2)`

`2log_7 x = 2 log_3 3`

`log_7 x= 1`

`1=log_7 7`

*There for x=7. The answer is x = 7*

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