A load of steel of mass 6000 kg rests on the flatbed of a truck. It is held in place by metal brackets that can exert a maximum horizontal force of 8000N. When the truck is traveling 20.0 m/s, what is the minimum stopping distance if the load is not to slide forward into the cab?

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First find the acceleration in the negative x direction the brackets can exert which is given by

`F=ma`

`rArr 8000=6000*a`

`rArr a=8000/6000=-1.33 m/s^2`

Then the time required to stop the truck without exceeding this acceleration can be determined from `v_f=v_o +at`

`rArr 0=20+(-1.33)t`

`rArr t=20/1.33=15.03 s`

The minimum stopping distance can be calculated using:

`s=v_ot+1/2at^2`

`rArr s=20*15.03+1/2*(-1.33)*(15.03)^2`

`rArr s=150.375 m`

Therefore, the minimum stopping distance if the load is not to slide forward into the cab is **150.375 m**.

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