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List all of the possible rational zeros of p(x)=2x^3-6x^2+7x-6.

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user1741790 | eNotes Newbie

Posted May 28, 2013 at 9:21 PM via web

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List all of the possible rational zeros of p(x)=2x^3-6x^2+7x-6.

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oldnick | (Level 1) Valedictorian

Posted May 30, 2013 at 2:50 AM (Reply #1)

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Ya'd to add Its the lonely rational solution for: `2x^2-2x+3 ` hasn't solutions. Indeed `Delta=4- 4 xx3xx2<=0`

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embizze | High School Teacher | (Level 1) Educator Emeritus

Posted May 29, 2013 at 4:07 AM (Answer #1)

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The rational root theorem states that a polynomial with integer coefficients in standard form with leading coefficient `a_n` and constant term `a_0` can only have rational roots of the form `p/q` where p divides the constant term (or is a factor of the constant term) and q divides the leading coefficient.

Given `p(x)=2x^3-6x^2+7x-6` we note that the coefficients are all integers and the polynomial is in standard form.

Then any possible rational root is of the form `p/q` where p is a factor of -6 and q is a factor of 2.


The possible rational roots are `+-1,+-2,+-3,+-6,+-1/2,+-3/2`

** Note that we left out `+-2/2` since this is really `+-1` and already in the list (also `+-6/2` for a similar reason).


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