Line j has a slope of -7/8. Line k is perpendicular to line j. What is the slope of line k?
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The product of the slopes of two perpendicular lines is -1.
We'll note the slope of the line j as `m_j` and the slope of the line k as `m_k` .
We'll compute the product of the slopes:
`m_(j)*m_(k) = -1`
`(-7/8)*m_(k) = -1`
`m_(k) = -1/(-7/8)`
`m_(k) = 8/7`
Therefore, the slope of the perpendicular line k is `m_(k) = 8/7` .
Line J m=-7/8
Formula of slope of line perpendicular or another line is:
m1m2=-1 where m1 is slope 1 and m2 is the slope we have to find
Take 8 on the other side as numerator and multiply by -1 take -7 as numerator therefore both the subtraction signs get cancelled.
therefore 8/7 is the slope of the K.
The slope of a line is always the negitave reciprocal of the slope of the line perpendicular to it.
Therefore, the slope of line k is 8/7
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