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`lim_(x->+oo)root(3)((6+9x+7x^2)/(1+27x^2))`

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user7230927 | Honors

Posted June 4, 2013 at 6:06 PM via web

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`lim_(x->+oo)root(3)((6+9x+7x^2)/(1+27x^2))`

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embizze | High School Teacher | (Level 1) Educator Emeritus

Posted June 4, 2013 at 6:28 PM (Answer #1)

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Find `lim_(x->oo)root(3)((7x^2+9x+6)/(27x^2+1))` :

`lim_(x->oo)root(3)((7x^2+9x+6)/(27x^2+1))`

`=root(3)(lim_(x->oo)(7x^2+9x+6)/(27x^2+1))`

`=root(3)(lim_(x->oo)(7+9/x+6/x^2)/(27+1/x^2))`

`=root(3)(7/27)`

`=root(3)(7)/3~~.637643728`

 

 

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