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Light enters a substance from air at 45.0 degrees to the normal. It continues through...
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We know that
where `theta_1` is the angle subtended between the incident ray and the normal to the interface, and `theta_2` is the angle subtended between the refracted ray and the normal to the interface. The quantities `n_1` and `n_2` are termed the refractive indices of media 1(air) and 2 (substance), respectively.
`theta_1=45^o , n_1=1.0`
The critical angle for this substance=53.62 degree.
Posted by pramodpandey on May 19, 2013 at 6:20 AM (Answer #1)
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