Let v1=(5,2,0), v2=(3,4,1), v3=(1,3,2), v4=(0,1,1) Is{v1,v2,v3,v4} a generating system for R^3. Is is a basis for R^3? why/why not?

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cosinusix | College Teacher | (Level 3) Assistant Educator

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If is generating `RR^3` iff any vector (x,y,z) of` RR^3` can be written  in the form `av_1+bv_2+cv+3+dv+4=(x,y,z)` for some (a,b,c,d) in `RR^4.`


Let's solve the condition for (a,b,c,d)






Let's try to find a solution with b=0














`3a=x+z-y `





Remember b=0

Therefore for any vector (x,y,z) we found a linear combination such that `(x,y,z)=av_1+bv_2+cv_3+dv_5. ` The expression of a,b=0,c, d are given above. Therefore the 4 vectors are generating `RR^3.`


`RR^3` is a 3 dimensional vector space. Any basis of `RR^3 ` contains 3 vectors. Therefore the 4 vectors `v_1, v_2, v_3, v_4` can't be a basis.



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