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Let pi_1 be the xy-plane and pi_2 be the yz-plane. (b) Find the angle between pi_1 and...
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The xy-plane has an equation 0x + 0y + z = 0 and the yz-plane is x + 0y + 0z = 0.
The angle `theta` between two planes is given by `cos theta = (0*1 + 0*0 + 1*0)/(sqrt(1+0+0)*sqrt(0+0+1))`
=> `cos theta = 0`
=> `theta = 90`
The angle between the plane pi_1 and the plane pi_2 is 90 degrees.
Posted by justaguide on February 12, 2013 at 7:11 AM (Answer #1)
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