Let f(x)=(x^3-2/x)^-6. Find f'(x)=
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Find the derivative of `f(x)=(x^3-2/x)^(-6)` :
We apply the general power rule (derived from the chain rule) `d/(dx)u^n=n u^(n-1)(du)/(dx)` assuming u is a differentiable function of x.
Let `u=x^3-2/x` so `(du)/(dx)=3x^2+2/x^2` .
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