Let f(x)=x^2 and g(x)=x-3. Evaluate each expression.

1. `(f _og)(-2)` and `(g_og)(7)`

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`f[g(x)]=(x-3)^2` `f[g(-2)]=(-2-3)^2=25`

`g[g(x)]=(x-3)-3=x-6` `g[g(7)]=7-6=1`

This is about composition of function.

In `(f_0g)(x)` we have to replace x in f(x) terms of x in g(x).

`f(x) = x^2`

`g(x) = x-3`

`(f_0g)(x) = (x-3)^2`

`(g_0g)(x) = (x-3-3) = (x-6)`

*Then we can write the answers as;*

`(f_0g)(-2) = (-2-3)^2 = 25`

`(g_0g)(7) = (7-6) = 1`

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