Let `f(x) = x^2+2x+9; x in RR` Determine the set of values of a real constant `lambda` for which the equation `f(x)=lambda` ; that f(x) has no real solution for x.



Asked on

1 Answer | Add Yours

jeew-m's profile pic

Posted on (Answer #1)

`f(x) = x^2+2x+9`

`x^2+2x+9 = lambda`

`x^2+2x+9-lambda = 0`

If the above quadratic function does not have real roots then the discriminant(Delta) should be less than 0.

`Delta = 4-4xx1xx(9-lambda)<0`



So for `f(x) = lambda` where there is no solutions `lambda<8`


We’ve answered 288,036 questions. We can answer yours, too.

Ask a question