# Let f (x)= (3x+1) CalculateĀ A) 2f(0)+f(-2) B) f (0)f(-2)

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In order to solve this question you must substitute each value of x into the equation and solve for f(x):

`f(0)=3(0)+1=1`

`f(-2)=3(-2)+1=-5`

Therefore:

`2f(0)+f(-2)=2(1)+(-5)=-3`

And:

`f(0)f(-2)=(1)(-5)=-5`