- In the lab, students generated and collected hydrogen gas according to the following equation:

Zn(s) + H2SO4(aq) à H2(g) + ZnSO4(aq)

- How many mL of hydrogen gas at STP were generated from 52.7 g of zinc metal?

### 1 Answer | Add Yours

Zn+H_2SO_4 rarr H_2+ZnSO_4

Mole mass

Zn = 65.38g/mol

Amount of Zn reacted = 52.7g = 52.7/65.38 mol = 0.8mol

Mole ratio

Zn:H_2 = 1:1

So amount of H_2 gas produced = 0.8mol

At STP 1 mol of gas holds a volume of 22.4L

Volume of 1mol of H_2 gas at STP = 22.4L

Volume of 0.8mol of H_2 gas at STP = 0.8xx22.4L = 17.92L

*So 17920ml of hydrogen gas will be produced*

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