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A lab designed a radio telescope with a diameter of 300 feet and a maximum depth of 38...
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The radio telescope designed by the lab has a diameter of 300 feet and a maximum depth of 38 feet.
The equation of the parabola representing the cross section of the telesope has to be determined given that the points (-150, 38) and (150, 38) lie on it.
The equation is of the form y = ax^2. Substituting the co-ordinates of any of the points given:
38 = a*150^2
=> a = `19/11250`
The required equation of the parabola is `y = (19/11250)*x^2`
Posted by justaguide on June 15, 2013 at 12:47 AM (Answer #1)
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