A kicker punts a football from 3 feet above the ground with an initial velocity of 47 feet per second.   Find the height (in feet) of the football 2 seconds after the punt. The height of the ball...

A kicker punts a football from 3 feet above the ground with an initial velocity of 47 feet per second.

 

Find the height (in feet) of the football 2 seconds after the punt.

The height of the ball is given by      `h(t)= -16t^2 + 47t + 3`

Asked on by loishy

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tiburtius | High School Teacher | (Level 1) Educator

Posted on

To find the height you simply put 2 instead of `t` into your formula for height.

`h(2)=-16cdot2^2+47cdot2+3=-16cdot4+94+3=33`

Hence the height of the football 2 seconds after the punt is 33 feet.

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