Better Students Ask More Questions.
Kapoor and Ramesh push a 1200 kg block horizontally in the same direction. Sunil...
1 Answer | add yours
We can use the Newton’s laws of motion here.
F=ma for the direction of force
At the force side we have two forces 500N and 300N. Resisting these forces we have frictional force of 200N.
`(500+300) -200 = 1200xxa`
`a = 600/1200 = 0.5 m/s^2`
So the acceleration of the block is 0.5m/s^2
Posted by jeew-m on August 25, 2013 at 7:25 AM (Answer #1)
Join to answer this question
Join a community of thousands of dedicated teachers and students.